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How much superpower does it take to hit a bullet in the air?

Since this is a quadratic equation, a diagram of the vertical position against time should have the shape of a parabola. Note that there are three variables here: position, time and acceleration. If I know two of them, I can solve the third. In this case, we only know the acceleration ( g ); We have no distance or time scales.

To determine the distance, I estimated the width of Wonder Women's wrist to be approximately 5 cm. To get around the time problem, I created any unit of time that I called false seconds. Here is a representation of the vertical position against time in fake seconds:

For the first part of this movement, the shape is parabolic, which means that the ball is actually moving upwards with a constant downward acceleration. But look at this jump in action after about 2 (wrong) seconds. That is not right. Well. With this data, we can do some fun things. I'm just going to ask a few questions and then go through the answers.

How long was the ball in the air? What is the real time scale?

Suppose my assessment of the distance scale was largely legitimate. Mostly. That means I can determine the vertical acceleration from the quadratic adjustment of the vertical ball movement. This acceleration is given in units of meters per square second instead of m / s 2 . If I set this acceleration for the counterfeit time equal to the actual acceleration, I can resolve the relationship between the counterfeit and the actual second: